averages Model Questions & Answers, Practice Test for ssc cgl tier 1 2023

Question :11

Abhishek purchased 140 shirts and 250 trousers @ Rs. 450 and @ Rs. 550 respectively. What should be the overall average selling price of shirts and trousers so that 40% profit is earned? (Rounded off to next integer)

Answer: (a)

Average selling price

= ${140 × 450 + 250 × 550}/{140 + 250} × 140/100$

= $200500/390 × 140/100$ = Rs. 720 (approx.)

Question :12

The average age of boys in the class is twice the number of girls in the class. The ratio of boys and girls in the class of 50 is 4 : 1. The total of the ages (in years) of the boys in the class is

Answer: (a)

Number of boys = $4/5 × 50$ = 40

Number of girls = $1/5 × 50$ = 10

Average age of boys = 2 × 10 = 20

Total ages of the boys = 40 × 20 = 800

Question :13

A race has three parts. The speed and time required to complete the individual parts for a runner is displayed on the following chart:

 Part IPart IIPart III
Speed (kmph)987.5
Time (minutes)5080100
What is the average speed of this runner ?

Answer: (a)

Average speed = Total Distance / Total time

= ${9{50}/60 + 8{80}/60 + 7.5{100}/60}/{50/60 + 80/60 + 100/60}$

= (45 + 64 + 75 ) / 23 = 184/23

= 8 kmph

Question :14

The average weight of a group of 53 girls was calculated as 58 kgs. It was later discovered that the weight of one of the girls was read as 65 kgs., whereas her actual weight was 45 kgs. What is the actual average weight of the group of 53 girls? (rounded off to two digits after decimal)

Answer: (d)

Increase in weight

= 65 – 45 = 20 kg.

∴ Increase in average

= $20/53$ = 0.38s

∴ Actual average weight

= 58 – 0.38 = 57.62

Question :15

The average marks of section A are 65 and that of section B are 70. If the average marks of both the sections combined are 67, then the ratio of number of students of section A to that of section B is

Answer: (c)

Section A

${x_1 + x_2 +....+ x_n}/n$ = 65

$x_1 + x_2 +....+ x_n$ = 65×n ...(1)

Section B

${y_1 + y_2 +....+ y_m}/m$ = 70

$y_1 + y_2 +....+ y_m$ = 70×m ...(2)

Combined Section

${y_1 + y_2 +....+ y_m}/m = 70$

65n + 70m = 67n + 67m ;

3m = 2n ; $3/2 = n/m$

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